Jika \(\sin \dfrac 12 x = \sqrt{\dfrac {x - 1}{2x}}\), maka \(\tan x = \dotso\)
(A) \(\sqrt{2x}\)
(B) \(\sqrt{x^2 - 1}\)
(C) \(\sqrt{\dfrac {x^2 - 1}{2x}}\)
(D) \(\dfrac {\sqrt{x^2 - 1}}{2x}\)
(E) \(\dfrac {x^2 - 1}{\sqrt{2x}}\)
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