Soal 19
\(\displaystyle \lim_{x \rightarrow \sim} \: \dfrac {3x^6 – 5x^2}{(1 – 3x^3)^2}\)
Soal 31
\(\displaystyle \lim_{x \rightarrow 2} \: \dfrac {x^2 – 4}{x – 2}\)
Soal 33
\(\displaystyle \lim_{x \rightarrow 4} \: \dfrac {x^2 – 4x}{x – 4}\)
\(\displaystyle \lim_{x \rightarrow \sim} \: \frac {(2x^2 – 7)^3 \:.\: (6x^2 + 2x)}{(3 + 4x^3) \:.\: (3x^5 + 7x)} = \dotso\)
(A) \(2\)
(B) \(4\)
(C) \(6\)
(D) \(8\)
(E) \(10\)
\(\displaystyle \lim_{x \rightarrow 2} \: \frac {3x – 6}{x – 3} = \dotso\)
(A) \(0\)
(B) \(1\)
(C) \(2\)
(D) \(3\)
(E) \(4\)
Jawab: D
\begin{equation*} \begin{split} & \lim_{x \rightarrow 2} \: \frac {3x – 6}{x – 2} \\\\ & \lim_{x \rightarrow 2} \: \frac {3 \cancel{(x – 2)}}{\cancel{x – 2}} \\\\ & 3 \end{split} \end{equation*}