100 gram air bersuhu 20ºC dicampur dengan 150 gram air bersuhu 80ºC. Berapakah suhu campuran?
\begin{equation*}
\begin{split}
Q_{\text{lepas}} & = Q_{\text{terima}} \\\\
m \:.\: c \:.\: \Delta T & = m \:.\: c \:.\: \Delta T \\\\
100 \:.\: \cancel{c} \:.\: (T- 20) & = 150 \:.\: \cancel{c} \:.\: (80 - T) \\\\
100T - 2.000 & = 12.000 - 150T \\\\
100T + 150T & = 12.000 + 2.000 \\\\
T & = 56^{\text{o}}\text{C}
\end{split}
\end{equation*}