Pembahasan Soal 1

Jawab: B

\begin{equation*}
\begin{split}
\left(\dfrac {1}{16}\right)^{x - 2} & = 64 \\\\
\left(2^{-4}\right)^{x - 2} & = 2^6 \\\\
2^{-4x + 8} & = 2^6 \\\\
\cancel{2}^{-4x + 8} & = \cancel{2}^6 \\\\
-4x + 8 & = 6 \\\\
-4x & = 6 - 8 \\\\
-4x & = -2 \\\\
x & = \frac 12
\end{split}
\end{equation*}

\(2a + 1 = 2 \:.\: \frac 12 + 1 = 2\)