Tentukan panjang dan arah dari vektor \(\overrightarrow p = \left( \begin{matrix} 8 \\ -6 \\ \end{matrix} \right)\).
\(\overrightarrow p = \left( \begin{matrix} 8 \\ -6 \\ \end{matrix} \right)\)
\begin{equation*}
\begin{split}
| \: \overrightarrow{p} \: | & = \sqrt{8^2 + (-6)^2} \\\\
| \: \overrightarrow{p} \: | & = \sqrt{64 + 36} \\\\
| \: \overrightarrow{p} \: | & = \sqrt{100} \\\\
| \: \overrightarrow{p} \: | & = 10
\end{split}
\end{equation*}
\begin{equation*}
\begin{split}
\tan \theta & = \frac {-6}{8} \\\\
\tan \theta & = - \frac 34 \\\\
\theta & = \tan ^{-1} \left(- \frac 34 \right)
\end{split}
\end{equation*}