Mol dan Volume

A.   Jumlah mol CH₄

\begin{equation*}
\begin{split}
\text{n} & = \frac {\text{V}}{22,4} \\\\
\text{n} & = \frac{11,2}{22,4} \\\\
\text{n} & = 0,5 \text{ mol } \ce{CH4}
\end{split}
\end{equation*}

B.   Massa CH₄

\begin{equation*}
\begin{split}
\text{n} & = \frac{\text{m}}{\text{Mr}} \\\\
0,5& = \frac{\text{m}}{ 12 + (4 \times 1)} \\\\
\text{m} & = 0,5 \times 16 \\\\
\text{m} & = 8 \text{ gram } \ce{CH4}
\end{split}
\end{equation*}