Metode Cramer

\(x = \dfrac {D_x}{D} = \dfrac{\begin{vmatrix} {\color {blue} 4} & 2 \\ {\color {blue} 5} & -1\end{vmatrix}}{\begin{vmatrix}3 & 2 \\ 2 & -1 \end{vmatrix}} = \dfrac {-4 - 10}{-3 - 4} = \dfrac {-14}{-7} = 2\)

\(y = \dfrac {D_y}{D} = \dfrac{\begin{vmatrix}3 & {\color {blue} 4} \\ 2 & {\color {blue} 5}\end{vmatrix}}{\begin{vmatrix}3 & 2 \\ 2 & -1 \end{vmatrix}} = \dfrac {15 - 8}{-3 - 4} = \dfrac {7}{-7} = -1\)