Hukum Avogadro

\begin{equation*}
\begin{split}
\left(\frac{N}{V}\right)_{\ce{NH3}} & = \left(\frac{N}{V}\right)_{\ce{O2}} \\\\
\frac{3 \times 10^{22}}{6} & = \frac{N}{8} \\\\
6N & = 8 \times 3 \times 10^{22} \\\\
N & = \frac{8 \times 3 \times 10^{22}}{6} \\\\
N & = 4 \times 10^{22} \text{ molekul } \ce{O2}
\end{split}
\end{equation*}

Jumlah molekul \( \ce{O2}\) = \(4 \times 10^{22}\) molekul

Jumlah atom \( \ce{O2}\) = \(8 \times 10^{22}\) atom