SUBSTITUSI TRIGONOMETRI
\(\sqrt{b^2 - (ax)^2} \rightarrow ax = b \sin \theta\)
\(\sqrt{(ax)^2 - b^2} \rightarrow ax = b \sec \theta\)
\(\sqrt{(ax)^2 + b^2} \rightarrow ax = b \tan \theta\)
\(\sqrt{b^2 - (ax)^2} \rightarrow ax = b \sin \theta\)
\(\sqrt{(ax)^2 - b^2} \rightarrow ax = b \sec \theta\)
\(\sqrt{(ax)^2 + b^2} \rightarrow ax = b \tan \theta\)